EASA / CAR Part-66 · Module 2 · 2.2 Mechanics · Cat B1/B2

Momentum & Collisions

Objective: show that momentum is always conserved in a collision, that kinetic energy is conserved only in a perfectly elastic one, and how the coefficient of restitution sets everything in between.

Two bodies on a trackdrag to rotate

Momentum & kinetic energy, before and after

Velocity A after
0m/s
Velocity B after
0m/s
Total momentum
0kg·m/s
Kinetic energy lost
0%
m1u1 + m2u2 = m1v1 + m2v2  ·  e = (v2 − v1) / (u1 − u2)

Perfectly elastic collision

Both momentum and kinetic energy are conserved. The bodies separate at the same relative speed at which they approached.

Momentum, p = mv, is conserved in every collision, without exception, provided no external force acts. That is a direct consequence of Newton's third law: whatever impulse A exerts on B, B exerts an equal and opposite impulse on A, so the total is unchanged. Momentum is a vector, so direction matters and velocities in opposite senses carry opposite signs.

Kinetic energy is a different matter. It is conserved only in a perfectly elastic collision, where the bodies separate at the same relative speed at which they approached. In every real collision some energy goes into permanent deformation, heat, sound and vibration, so kinetic energy is lost even though momentum is not. The extreme case is a perfectly inelastic collision, where the bodies stick together and move off with a common velocity; that condition loses the most kinetic energy of any collision with the same momentum.

The coefficient of restitution e measures where a collision sits between those extremes: e = 1 is perfectly elastic, e = 0 is perfectly inelastic, and real materials fall somewhere between. This is exactly the reasoning behind crumple zones and energy-absorbing structures, which are designed to be inelastic on purpose so that the energy is dissipated by the structure rather than transmitted to the occupants.