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Section 7.16

Aircraft Weight & Balance

Centre-of-gravity and balance-limit calculation, the weighing procedure and precautions, and the weight-and-balance documentation.

Notes

Weight & balance, summary notes

Main ideas
  • Weight and balance establishes the aircraft's empty weight and centre of gravity (CG) and confirms the CG stays within the forward and aft limits for every loading, a CG outside limits makes the aircraft unstable or uncontrollable.
  • The DATUM is a defined reference plane; the ARM is the horizontal distance of a weight from the datum, and the MOMENT is weight × arm. The CG is the total moment divided by the total weight, measured from the datum.
  • Weighing procedure: use the approved weighing schedule, put the aircraft in the defined configuration (fuel and fluids drained or accounted for, specified equipment fitted/removed, state recorded), and use calibrated, in-date load cells or scales at the jacking or wheel points.
  • Weigh in a closed, draught-free, dry hangar to avoid wind and rain errors, and level the aircraft to its datum using the built-in level provision.
  • Record the reaction at each weighing point and its arm; sum the moments and divide by the total weight to find the empty-weight CG, then compare against the limits.
  • Account for TARE, the weight of chocks, jacks and adapters on the scales, and subtract it, and record the true empty-weight configuration.
  • The weight-and-balance report and the loading/mass-and-balance documentation are updated and certified after any weighing or major modification affecting weight.
  • ⚠ Exam trap: Moment = Weight × Arm, and CG = Σ Moments ÷ Σ Weights measured from the datum, and remember to remove tare.
Key formulas
Moment
Moment = Weight × Arm
Centre of gravity
CG = Σ Moments ÷ Σ Weights (from the datum)
Net weight
scale reading − tare = actual reaction
Solved examples
  1. Datum at the nose. Nose gear 500 kg at arm 1.0 m; main gear 1500 kg at arm 5.0 m. Find the CG.

    Total weight = 2000 kg. Total moment = (500 × 1.0) + (1500 × 5.0) = 500 + 7500 = 8000 kg·m. CG = 8000 ÷ 2000 = 4.0 m aft of the datum.

  2. Why is the aircraft weighed in a closed hangar and levelled to its datum?

    Wind produces aerodynamic lift or download and rain adds weight, both falsifying the reading, so the hangar must be draught-free and dry. Levelling to the datum ensures the arms used in the calculation match the schedule; an out-of-level aircraft gives wrong arms and therefore a wrong CG.

Mind map

Weight & balance concept map

Weight & Balance

Quiz

Weight & balance quiz

Weight & Balance, quiz

Ref 7.1610 of 17Pass 75%
  1. 1. An aircraft weighs 2400 kg with its centre of gravity 2.5 m aft of datum. The total moment about datum is:

    6000 kg·m
    960 kg·m
    2402.5 kg·m
  2. 2. Total moment is 9000 kg·m and total weight is 3000 kg. The centre of gravity lies:

    3.0 m aft of datum
    27 000 m aft of datum
    0.33 m aft of datum
  3. 3. An aircraft of 2000 kg has its CG at 2.0 m. Adding 100 kg of baggage at 4.5 m moves the CG to approximately:

    2.12 m
    2.25 m
    3.25 m
  4. 4. Moment in a weight-and-balance calculation equals:

    Weight × arm
    Weight ÷ arm
    Weight + arm
  5. 5. Centre of gravity is:

    Total moment ÷ total weight
    Total weight ÷ total moment
    The heaviest point
  6. 6. The arm is the distance of a weight from the:

    Datum
    Nose gear
    Wing tip
  7. 7. Nose gear 500 kg at 1 m, mains 1500 kg at 5 m. The CG is:

    4.0 m from datum
    3.0 m
    5.0 m
  8. 8. An aircraft is weighed in:

    A closed, draught-free, dry hangar
    The open, in any weather
    A pressurised chamber
  9. 9. Before recording weights, the aircraft is:

    Levelled to its datum
    Fully fuelled
    Jacked to maximum height
  10. 10. Tare weight on the scales is:

    Subtracted from the reading
    Added to the reading
    Ignored