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Section 8.3(b)

Load Factor, Flight Envelope & Lift Augmentation

Load factor and manoeuvre stall speed, the V-n diagram and manoeuvring speed, and flaps/slats as lift-augmentation devices.

Notes

Load factor & flight envelope, summary notes

Main ideas
  • Load factor n = L/W, expressed in 'g'. Straight and level flight is 1 g; in a balanced level turn n = 1/cos φ, so a 60° bank needs 2 g, the wing (and everything in the aircraft) effectively weighs double.
  • Raising the load factor raises the stall speed: V_s(n) = V_s1g·√n. At 2 g the stall speed is √2 ≈ 1.41 times the 1 g value, so a steep turn can provoke an accelerated stall well above the normal stalling speed.
  • The V-n (flight-envelope) diagram plots airspeed against load factor. It is bounded below the manoeuvre by the aerodynamic stall (C_Lmax line), above by the structural limit load factor (e.g. +2.5 g / −1.0 g for a transport), and at high speed by V_NE and gust lines.
  • Manoeuvring speed V_A is the speed at which the aircraft reaches limit load exactly as it stalls; below V_A full control deflection makes the wing stall before it can overstress the structure, so V_A is a protective speed, above it, full deflection can break the airframe.
  • Lift-augmentation devices lower the take-off and landing speeds: trailing-edge FLAPS add camber to raise C_Lmax and lower the stall speed (also adding drag); leading-edge SLATS and SLOTS re-energise the boundary layer to delay separation to a higher AoA; combined, they let the wing fly slower.
  • ⚠ Exam trap: flaps raise C_Lmax and lower the stall speed but do NOT increase the maximum angle of attack, slats/slots do that. And exceeding V_A with full/abrupt control inputs can overstress the airframe; the stall only protects you below V_A.
Key formulas
Load factor
n = L / W
Load factor in a level turn
n = 1 / cos φ
Stall speed under load
V_s(n) = V_s1g · √n
Solved examples
  1. An aircraft stalls at 60 kt in level flight. What is its stall speed in a steady 60° banked level turn?

    A 60° bank gives n = 1/cos 60° = 2 g. Stall speed rises by √n = √2 ≈ 1.41, so V_s = 60 × 1.41 ≈ 85 kt. The extra lift needed to turn brings the wing to its stalling angle at a much higher speed, the accelerated stall.

Mind map

Load factor & envelope concept map

Load Factor & Flight Envelope

Quiz

Load factor & flight envelope quiz

Load Factor & Flight Envelope, quiz

Ref 8.3(b)8 of 14Pass 75%
  1. 1. In the banked turn shown, the component marked H is the horizontal component of lift. Its function is to:

    LHVWφ
    Provide the centripetal force that turns the aircraft
    Balance the weight
    Oppose the drag
  2. 2. In a level turn at 60° angle of bank, the load factor is:

    2
    1.41
    1.15
  3. 3. If the load factor in a turn is 2, the stall speed increases by a factor of:

    1.41
    2
    4
  4. 4. Load factor n is defined as:

    Lift ÷ weight
    Weight ÷ lift
    Thrust ÷ drag
  5. 5. In a balanced 60° banked level turn the load factor is:

    2 g
    1 g
    3 g
  6. 6. Stall speed under load factor n is:

    V_s1g·√n
    V_s1g·n
    V_s1g ÷ n
  7. 7. At 2 g the stall speed rises by a factor of about:

    1.41 (√2)
    2.0
    0.5
  8. 8. The V-n diagram plots:

    Airspeed against load factor
    Altitude against temperature
    Thrust against drag